(2ycosx+sin^4x)dx=sinxdy

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Solution for (2ycosx+sin^4x)dx=sinxdy equation: 


Simplifying
(2ycosx + sin4x) * dx = sinxdy

Reorder the terms for easier multiplication:
dx(2cosxy + in4sx) = sinxdy
(2cosxy * dx + in4sx * dx) = sinxdy
(2cdosx2y + din4sx2) = sinxdy

Solving
2cdosx2y + din4sx2 = dinsxy

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1din4sx2' to each side of the equation.
2cdosx2y + din4sx2 + -1din4sx2 = dinsxy + -1din4sx2

Combine like terms: din4sx2 + -1din4sx2 = 0
2cdosx2y + 0 = dinsxy + -1din4sx2
2cdosx2y = dinsxy + -1din4sx2

Divide each side by '2dosx2y'.
c = 0.5ino-1x-1 + -0.5in4o-1y-1

Simplifying
c = 0.5ino-1x-1 + -0.5in4o-1y-1

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